- A function is said to have a vertical asymptote wherever the limit on the left or right (or both) is either positive or negative infinity. For example, the function f(x)=(x^2+1)/((2x+3)(x−5)) has a vertical asymptote at x=5
For each of the following limits, enter either ‘P’ for positive infinity, ‘N’ for negative infinity, or ‘D’ when the limit simply does not exist.
lim x→5 − x 2 +1(2x+3)(x−5) = limx→5−x2+1(2x+3)(x−5)=
lim x→5 + x 2 +1(2x+3)(x−5) = limx→5+x2+1(2x+3)(x−5)=
lim x→5 x 2 +1(2x+3)(x−5) = limx→5×2+1(2x+3)(x−5)=
- Evaluate the following limits. If needed, enter INF for ∞ and MINF for −∞.
lim x→∞ (1+2x)/(3−5x) =
lim x→−∞ (1+2x)/(3−5x) =
- Evaluate the following limits. If needed, enter INF for ∞ and MINF for −∞.
lim x→∞ (8x^3−6x^2)/(−9x10−2x−5x^3)
lim x→−∞ (8x^3−6x^2)/(−9x10−2x−5x^3)
- Evaluate the following limits. If needed, enter INF for ∞ and MINF for −∞.
lim x→∞ (7x+88x^2)/(−5x+5)=
lim x→−∞ (7x+88x^2)/(−5x+5)=
- Evaluate the following limits. If needed, enter INF for ∞ and MINF for −∞.
limx→∞(√(3+3x^2))/(2+5x))=
limx→−∞(√(3+3x^2))/(2+5x))=
- Enter I for ∞, -I for −∞, and DNE if the limit does not exist.
limx→∞(√(4x^2+x)−2x)
Limit =
- Enter I for ∞, -I for −∞, and DNE if the limit does not exist.
limx→∞(√(x^2+5)- √(x^2−10))
Limit =
- Note: Input inf for ∞∞, -inf for −∞−∞ or dne if needed.
limx→∞9cosx
Limit =
- Evaluate the following limits. If needed, enter ‘INF’ for ∞ and ‘-INF’ for −∞.
limx→∞(−33x^2−15x^3)=
limx→−∞(−33x^2−15x^3)=
- Evaluate the following limit
limx→∞((9−√(x))/( 9+√(x))
- Evaluate the following limits. If needed, enter inf for ∞ and -inf −∞.
limx→∞x^2(−2+9x)(−9−3x)=
limx→−∞x^2(−2+9x)(−9−3x)=
- Find the equations of the horizontal asymptotes and the vertical asymptotes of f(x)f(x). If there are no asymptotes of a given type, enter NONE. If there is more than one asymptote of a given type, give a comma separated list (i.e.: 1, 2,…).
f(x)=((x^2+x−6)/(3x^2+7x−6))
Horizontal asymptotes: y=
Vertical Asymptotes: x=
- Evaluate the following limits, use “infinity” for “∞” and “-infinity” for “−∞”.
limx→5−((2)/(x−5)^3)) =
limx→3+((2)/(x−3))=
limx→3−((2)/(x−3))=
limx→−7−((1)/(x^2(x+7))=